What is the answer to 27^{2x+2}=81^{5-x} ?

The answer to 27^{2x+2}=81^{5-x} is x= 7/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

27^{2x+2}=81^{5-x}

2 7^{2 x + 2} = 8 1^{5 - x}

x = \frac{7}{5}

Decimal Notation

x = 1.4

Solution steps

2 7^{2 x + 2} = 8 1^{5 - x}

Apply exponent rules

3 (2 x + 2) = 4 (5 - x)

Solve

3 (2 x + 2) = 4 (5 - x) : x = \frac{7}{5}

x = \frac{7}{5}

2^{x - 4} = 64

3^{y + 1} = 4^{y}

3^{x} = 4^{x}

e^{x} - 7 = 8 e^{- x}

9^{3 x} - 2 \cdot 3^{3 x + 1} - 27 = 0

What is the answer to 27^{2x+2}=81^{5-x} ?
The answer to 27^{2x+2}=81^{5-x} is x= 7/5
Solve for x: 27^{2x+2}=81^{5-x}
The solution is x= 7/5