What is the answer to 3^{y+1}=4^y ?

The answer to 3^{y+1}=4^y is y=(ln(3))/(2ln(2)-ln(3))

Solve for y: 3^{y+1}=4^y

The solution is y=(ln(3))/(2ln(2)-ln(3))

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3^{y + 1} = 4^{y}

y = \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

Decimal Notation

y = 3.81884 \dots

Solution steps

3^{y + 1} = 4^{y}

Apply exponent rules

(y + 1) ln (3) = y ln (4)

Solve

(y + 1) ln (3) = y ln (4) : y = \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

y = \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

3^{x} = 4^{x}

e^{x} - 7 = 8 e^{- x}

9^{3 x} - 2 \cdot 3^{3 x + 1} - 27 = 0

2^{x^{2} - 4} = 8^{- x}

3^{x} = 2^{x + 2}

What is the answer to 3^{y+1}=4^y ?
The answer to 3^{y+1}=4^y is y=(ln(3))/(2ln(2)-ln(3))
Solve for y: 3^{y+1}=4^y
The solution is y=(ln(3))/(2ln(2)-ln(3))