What is the answer to 2^{x^2-4}=8^{-x} ?

The answer to 2^{x^2-4}=8^{-x} is x=1,x=-4

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2^{x^2-4}=8^{-x}

2^{x^{2} - 4} = 8^{- x}

x = 1, x = - 4

Solution steps

2^{x^{2} - 4} = 8^{- x}

Apply exponent rules

x^{2} - 4 = - 3 x

Solve

x^{2} - 4 = - 3 x : x = 1, x = - 4

x = 1, x = - 4

3^{x} = 2^{x + 2}

3^{2 x + 1} = 5^{x + 1}

x, f (2 e^{x} + 1) = 3

4^{3 x + 1} = 2

e^{4 x} = 81

What is the answer to 2^{x^2-4}=8^{-x} ?
The answer to 2^{x^2-4}=8^{-x} is x=1,x=-4
Solve for x: 2^{x^2-4}=8^{-x}
The solution is x=1,x=-4