What is the answer to 27^x(9^{2x-1})=3^{x+4} ?

The answer to 27^x(9^{2x-1})=3^{x+4} is x=1

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27^x(9^{2x-1})=3^{x+4}

2 7^{x} (9^{2 x - 1}) = 3^{x + 4}

x = 1

Solution steps

2 7^{x} (9^{2 x - 1}) = 3^{x + 4}

Apply exponent rules

3 x + 2 (2 x - 1) = x + 4

Solve

3 x + 2 (2 x - 1) = x + 4 : x = 1

x = 1

2^{8 x + 3} = 2

\frac{27}{9 ^{x}} = 3^{x - 1}

3 6^{2 x - 7} = 6^{x - 5}

3^{x + 1} - 2 = 25

8^{x^{2}} = 9^{x}

What is the answer to 27^x(9^{2x-1})=3^{x+4} ?
The answer to 27^x(9^{2x-1})=3^{x+4} is x=1
Solve for x: 27^x(9^{2x-1})=3^{x+4}
The solution is x=1