What is the answer to 4^{3x-1}= 1/(8^{x-1)} ?

The answer to 4^{3x-1}= 1/(8^{x-1)} is x= 5/9

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4^{3x-1}= 1/(8^{x-1)}

4^{3 x - 1} = \frac{1}{8 ^{x - 1}}

x = \frac{5}{9}

Decimal Notation

x = 0.55555 \dots

Solution steps

4^{3 x - 1} = \frac{1}{8 ^{x - 1}}

Apply exponent rules

2 (3 x - 1) = 3 (- x + 1)

Solve

2 (3 x - 1) = 3 (- x + 1) : x = \frac{5}{9}

x = \frac{5}{9}

Verify Solutions:

x = \frac{5}{9}

True

The solution is

x = \frac{5}{9}

r, y = r (x - 1)^{r} + 1

2^{x^{2}} - 4^{3 x - 4} = 0

(x) = 3^{- x}

x, x + y + e^{x y} = 0

What is the answer to 4^{3x-1}= 1/(8^{x-1)} ?
The answer to 4^{3x-1}= 1/(8^{x-1)} is x= 5/9
Solve for x: 4^{3x-1}= 1/(8^{x-1)}
The solution is x= 5/9