What is the answer to sqrt(4^{x+1)}=\sqrt[3]{16} ?

The answer to sqrt(4^{x+1)}=\sqrt[3]{16} is x= 1/3

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sqrt(4^{x+1)}=\sqrt[3]{16}

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

Apply exponent rules

(x + 1) \frac{1}{2} = \frac{2}{3}

Solve

(x + 1) \frac{1}{2} = \frac{2}{3} : x = \frac{1}{3}

x = \frac{1}{3}

4^{x + 1} = 8^{x - 1}

8^{5 x - 7} = 6

9 = (\frac{1}{3})^{- x}

2^{x + 3} = 8^{x - 2}

4^{- x} = 64

What is the answer to sqrt(4^{x+1)}=\sqrt[3]{16} ?
The answer to sqrt(4^{x+1)}=\sqrt[3]{16} is x= 1/3
Solve for x: sqrt(4^{x+1)}=\sqrt[3]{16}
The solution is x= 1/3