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Popular >

solvefor x,2^x+1=2^y

Solution

solve for

x, 2^{x} + 1 = 2^{y}

Solution

x = \frac{ln ( 2 ^{y} - 1 )}{ln ( 2 )}

Solution steps

2^{x} + 1 = 2^{y}

Move

1

to the right side

2^{x} = 2^{y} - 1

Apply exponent rules

x ln (2) = ln (2^{y} - 1)

Solve

x ln (2) = ln (2^{y} - 1) : x = \frac{ln ( 2 ^{y} - 1 )}{ln ( 2 )}

x = \frac{ln ( 2 ^{y} - 1 )}{ln ( 2 )}

Popular Examples

16=5+16e^{x(34)}

16 = 5 + 16 e^{x (34)}

2^{x+2}=3^{x+1}

2^{x + 2} = 3^{x + 1}

1.5 (4)^{2 x} = 12

5^{(2 x + 1)} = 25

(1/9)^{3x}=27^{-(x+3)}

(\frac{1}{9})^{3 x} = 2 7^{- (x + 3)}

Frequently Asked Questions (FAQ)

What is the answer to solvefor x,2^x+1=2^y ?
The answer to solvefor x,2^x+1=2^y is x=(ln(2^y-1))/(ln(2))