What is the answer to 3^{x+4}=6^{2x-5} ?

The answer to 3^{x+4}=6^{2x-5} is x=(5ln(6)+4ln(3))/(ln(12))

Solve for x: 3^{x+4}=6^{2x-5}

The solution is x=(5ln(6)+4ln(3))/(ln(12))

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3^{x + 4} = 6^{2 x - 5}

x = \frac{5 ln ( 6 ) + 4 ln ( 3 )}{ln ( 12 )}

Decimal Notation

x = 5.37374 \dots

Solution steps

3^{x + 4} = 6^{2 x - 5}

Apply exponent rules

(x + 4) ln (3) = (2 x - 5) ln (6)

Solve

(x + 4) ln (3) = (2 x - 5) ln (6) : x = \frac{5 ln ( 6 ) + 4 ln ( 3 )}{ln ( 12 )}

x = \frac{5 ln ( 6 ) + 4 ln ( 3 )}{ln ( 12 )}

5 (2^{x}) = 4

x, 3^{8 x} = 4^{- x - 7}

(\frac{3}{5})^{x} = \frac{9}{25}

6^{x + 1} - 6^{x} = 1080

4^{X + 3} \cdot 8^{2 X - 1} = 2

What is the answer to 3^{x+4}=6^{2x-5} ?
The answer to 3^{x+4}=6^{2x-5} is x=(5ln(6)+4ln(3))/(ln(12))
Solve for x: 3^{x+4}=6^{2x-5}
The solution is x=(5ln(6)+4ln(3))/(ln(12))