Solution
Solution
+1
Decimal Notation
Solution steps
Apply exponent rules
Solve
Popular Examples
sqrt(2^{3x+5)}=9^{x+1}5^{x^2}=25^{5/2 x-2}2^x=8^{x+2}(0.5)^x-2^x-(0.5)^{2x+3}=1(sqrt(x))^x=(x)^{sqrt(x)}
Frequently Asked Questions (FAQ)
What is the answer to 87=35^x ?
The answer to 87=35^x is x=(ln(87))/(ln(35))Solve for x: 87=35^x
The solution is x=(ln(87))/(ln(35))