What are the solutions to the equation x^2-7x+18=0 ?

The solutions to the equation x^2-7x+18=0 are x= 7/2+i(sqrt(23))/2 ,x= 7/2-i(sqrt(23))/2

Find the zeros of x^2-7x+18=0

The zeros of x^2-7x+18=0 are x= 7/2+i(sqrt(23))/2 ,x= 7/2-i(sqrt(23))/2

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x^{2} - 7 x + 18 = 0

x = \frac{7}{2} + i \frac{23}{2}, x = \frac{7}{2} - i \frac{23}{2}

Solution steps

x^{2} - 7 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

(- 7)^{2} - 4 \cdot 1 \cdot 18 : 23 i

x_{1, 2} = \frac{- ( - 7 ) \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 23 i}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 23 i}{2 \cdot 1}

x = \frac{- ( - 7 ) + 23 i}{2 \cdot 1} : \frac{7}{2} + i \frac{23}{2}

x = \frac{- ( - 7 ) - 23 i}{2 \cdot 1} : \frac{7}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2} + i \frac{23}{2}, x = \frac{7}{2} - i \frac{23}{2}

x^{2} + 12 x + 36 = 0

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x^{2} - 121 < 0

3 x^{2} - 192 = 0

e^{i x} - e^{- i x}

What are the solutions to the equation x^2-7x+18=0 ?
The solutions to the equation x^2-7x+18=0 are x= 7/2+i(sqrt(23))/2 ,x= 7/2-i(sqrt(23))/2
Find the zeros of x^2-7x+18=0
The zeros of x^2-7x+18=0 are x= 7/2+i(sqrt(23))/2 ,x= 7/2-i(sqrt(23))/2