What is the answer to 5^{x-1}=3 ?

The answer to 5^{x-1}=3 is x=(ln(3))/(ln(5))+1

Solve for x: 5^{x-1}=3

The solution is x=(ln(3))/(ln(5))+1

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5^{x - 1} = 3

x = \frac{ln ( 3 )}{ln ( 5 )} + 1

Decimal Notation

x = 1.68260 \dots

Solution steps

5^{x - 1} = 3

Apply exponent rules

(x - 1) ln (5) = ln (3)

Solve

(x - 1) ln (5) = ln (3) : x = \frac{ln ( 3 )}{ln ( 5 )} + 1

x = \frac{ln ( 3 )}{ln ( 5 )} + 1

x, x y = e^{2 x + y}

6 4^{x - 1} = 1 6^{2 x - 2}

14 (2 + e^{- x})^{- 1} = 3

5 (5^{2 x}) - 26 (5^{x}) + 5 = 0

\frac{13}{2 + e ^{x}} = 4

What is the answer to 5^{x-1}=3 ?
The answer to 5^{x-1}=3 is x=(ln(3))/(ln(5))+1
Solve for x: 5^{x-1}=3
The solution is x=(ln(3))/(ln(5))+1