What is the answer to 4^{y+1}=8^{2y-1} ?

The answer to 4^{y+1}=8^{2y-1} is y= 5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{y+1}=8^{2y-1}

4^{y + 1} = 8^{2 y - 1}

y = \frac{5}{4}

Decimal Notation

y = 1.25

Solution steps

4^{y + 1} = 8^{2 y - 1}

Apply exponent rules

2 (y + 1) = 3 (2 y - 1)

Solve

2 (y + 1) = 3 (2 y - 1) : y = \frac{5}{4}

y = \frac{5}{4}

e^{x^{2} - x} = e^{2}

e^{2 x + 3} = 5

3^{2 x - 2} = 9^{3 x + 2}

2^{2 x} \cdot 5^{x} = 8000

(\frac{5}{4})^{x} = 1650.35

What is the answer to 4^{y+1}=8^{2y-1} ?
The answer to 4^{y+1}=8^{2y-1} is y= 5/4
Solve for y: 4^{y+1}=8^{2y-1}
The solution is y= 5/4