What is the answer to 4^x=23 ?

The answer to 4^x=23 is x=(ln(23))/(2ln(2))

The solution is x=(ln(23))/(2ln(2))

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4^x=23

4^{x} = 23

x = \frac{ln ( 23 )}{2 ln ( 2 )}

Solution steps

4^{x} = 23

Apply exponent rules

x ln (4) = ln (23)

Solve

x ln (4) = ln (23) : x = \frac{ln ( 23 )}{2 ln ( 2 )}

x = \frac{ln ( 23 )}{2 ln ( 2 )}

e^{5 x} = 6

(\frac{1}{2})^{3 x} = 8

x, 2 t = e^{x} - e^{- x}

e^{2} x = 2 e^{x}

7^{x^{2} + 2 x} = 4 9^{- 3 x - 5}