What is the answer to 7^{x^2+2x}=49^{-3x-5} ?

The answer to 7^{x^2+2x}=49^{-3x-5} is x=-4+sqrt(6),x=-4-sqrt(6)

Solve for x: 7^{x^2+2x}=49^{-3x-5}

The solution is x=-4+sqrt(6),x=-4-sqrt(6)

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7^{x^{2} + 2 x} = 4 9^{- 3 x - 5}

x = - 4 + 6, x = - 4 - 6

Solution steps

7^{x^{2} + 2 x} = 4 9^{- 3 x - 5}

Apply exponent rules

x^{2} + 2 x = 2 (- 3 x - 5)

Solve

x^{2} + 2 x = 2 (- 3 x - 5) : x = - 4 + 6, x = - 4 - 6

x = - 4 + 6, x = - 4 - 6

2^{4 x - 1} = 3 2^{x + 1}

e^{2 x} = e^{3 - x}

x, 2^{x} + 2^{y} = 10

1 1^{2 x + 5} = 1

9^{b} = 81

What is the answer to 7^{x^2+2x}=49^{-3x-5} ?
The answer to 7^{x^2+2x}=49^{-3x-5} is x=-4+sqrt(6),x=-4-sqrt(6)
Solve for x: 7^{x^2+2x}=49^{-3x-5}
The solution is x=-4+sqrt(6),x=-4-sqrt(6)