What is the answer to solvefor x,2^x+2^y=10 ?

The answer to solvefor x,2^x+2^y=10 is x=(ln(10-2^y))/(ln(2))

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solvefor x,2^x+2^y=10

solve for

x, 2^{x} + 2^{y} = 10

x = \frac{ln ( 10 - 2 ^{y} )}{ln ( 2 )}

Solution steps

2^{x} + 2^{y} = 10

Move

2^{y}

to the right side

2^{x} = 10 - 2^{y}

Apply exponent rules

x ln (2) = ln (10 - 2^{y})

Solve

x ln (2) = ln (10 - 2^{y}) : x = \frac{ln ( 10 - 2 ^{y} )}{ln ( 2 )}

x = \frac{ln ( 10 - 2 ^{y} )}{ln ( 2 )}

1 1^{2 x + 5} = 1

9^{b} = 81

2^{x + 1} + 2^{x + 3} = 320

3^{x + 2} = 3^{7}

e^{x} - 3 e^{- x} = 2

What is the answer to solvefor x,2^x+2^y=10 ?
The answer to solvefor x,2^x+2^y=10 is x=(ln(10-2^y))/(ln(2))