What is the answer to 1-e^{(-0.75x)}=0.4268 ?

The answer to 1-e^{(-0.75x)}=0.4268 is x=-(ln(0.5732))/(0.75)

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1-e^{(-0.75x)}=0.4268

1 - e^{(- 0.75 x)} = 0.4268

x = - \frac{ln ( 0.5732 )}{0.75}

Solution steps

1 - e^{(- 0.75 x)} = 0.4268

Move

1

to the right side

- e^{- 0.75 x} = - 0.5732

Divide both sides by

- 1

e^{- 0.75 x} = 0.5732

Apply exponent rules

- 0.75 x = ln (0.5732)

Solve

- 0.75 x = ln (0.5732) : x = - \frac{ln ( 0.5732 )}{0.75}

x = - \frac{ln ( 0.5732 )}{0.75}

4 \cdot 3^{x + 1} - 9^{x} = 27

100 = 200 e^{- 0.06 x}

x^{2} e^{- x} = x e^{- x}

7^{2 - x} - 4 9^{2 - x} + 42 = 0

- \frac{1}{81} = - 3^{x}

What is the answer to 1-e^{(-0.75x)}=0.4268 ?
The answer to 1-e^{(-0.75x)}=0.4268 is x=-(ln(0.5732))/(0.75)