What is the answer to 3^{3x-4}=2^{3x-4} ?

The answer to 3^{3x-4}=2^{3x-4} is x=(-4ln(2)+4ln(3))/(3(-ln(2)+ln(3)))

Solve for x: 3^{3x-4}=2^{3x-4}

The solution is x=(-4ln(2)+4ln(3))/(3(-ln(2)+ln(3)))

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3^{3 x - 4} = 2^{3 x - 4}

x = \frac{- 4 ln ( 2 ) + 4 ln ( 3 )}{3 ( - ln ( 2 ) + ln ( 3 ) )}

Decimal Notation

x = 1.33333 \dots

Solution steps

3^{3 x - 4} = 2^{3 x - 4}

Apply exponent rules

(3 x - 4) ln (3) = (3 x - 4) ln (2)

Solve

(3 x - 4) ln (3) = (3 x - 4) ln (2) : x = \frac{- 4 ln ( 2 ) + 4 ln ( 3 )}{3 ( - ln ( 2 ) + ln ( 3 ) )}

x = \frac{- 4 ln ( 2 ) + 4 ln ( 3 )}{3 ( - ln ( 2 ) + ln ( 3 ) )}

2^{0.6 x} - 3 = 0

3^{2 x + 1} + 3^{x + 2} = 3 \frac{1}{3}

8^{x + 1} = 1

9 e^{3 x} = 1

a, 3^{a} + 4^{b} = 5^{c}

What is the answer to 3^{3x-4}=2^{3x-4} ?
The answer to 3^{3x-4}=2^{3x-4} is x=(-4ln(2)+4ln(3))/(3(-ln(2)+ln(3)))
Solve for x: 3^{3x-4}=2^{3x-4}
The solution is x=(-4ln(2)+4ln(3))/(3(-ln(2)+ln(3)))