What is the answer to solvefor a,3^a+4^b=5^c ?

The answer to solvefor a,3^a+4^b=5^c is a=(ln(5^c-4^b))/(ln(3))

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solvefor a,3^a+4^b=5^c

solve for

a, 3^{a} + 4^{b} = 5^{c}

a = \frac{ln ( 5 ^{c} - 4 ^{b} )}{ln ( 3 )}

Solution steps

3^{a} + 4^{b} = 5^{c}

Move

4^{b}

to the right side

3^{a} = 5^{c} - 4^{b}

Apply exponent rules

a ln (3) = ln (5^{c} - 4^{b})

Solve

a ln (3) = ln (5^{c} - 4^{b}) : a = \frac{ln ( 5 ^{c} - 4 ^{b} )}{ln ( 3 )}

a = \frac{ln ( 5 ^{c} - 4 ^{b} )}{ln ( 3 )}

4 e^{4 x} = 8

3^{x + 6} = 7

5^{(x + 3)} = 2 5^{(x - 1)}

2^{x + 5} + 2^{x + 4} + 2^{x + 3} = 28

12 = 25 e^{- (\frac{1}{5}) p}

What is the answer to solvefor a,3^a+4^b=5^c ?
The answer to solvefor a,3^a+4^b=5^c is a=(ln(5^c-4^b))/(ln(3))