What is the answer to 3^{x+6}=7 ?

The answer to 3^{x+6}=7 is x=(ln(7))/(ln(3))-6

Solve for x: 3^{x+6}=7

The solution is x=(ln(7))/(ln(3))-6

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3^{x + 6} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} - 6

Decimal Notation

x = - 4.22875 \dots

Solution steps

3^{x + 6} = 7

Apply exponent rules

(x + 6) ln (3) = ln (7)

Solve

(x + 6) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} - 6

x = \frac{ln ( 7 )}{ln ( 3 )} - 6

5^{(x + 3)} = 2 5^{(x - 1)}

2^{x + 5} + 2^{x + 4} + 2^{x + 3} = 28

12 = 25 e^{- (\frac{1}{5}) p}

x, 1 0^{x} = 38 z

9^{- x} = \frac{1}{3}

What is the answer to 3^{x+6}=7 ?
The answer to 3^{x+6}=7 is x=(ln(7))/(ln(3))-6
Solve for x: 3^{x+6}=7
The solution is x=(ln(7))/(ln(3))-6