What is the answer to 63=19^x ?

The answer to 63=19^x is x=(ln(63))/(ln(19))

The solution is x=(ln(63))/(ln(19))

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63=19^x

63 = 1 9^{x}

x = \frac{ln ( 63 )}{ln ( 19 )}

Decimal Notation

x = 1.40710 \dots

Solution steps

63 = 1 9^{x}

Apply exponent rules

ln (63) = x ln (19)

Solve

ln (63) = x ln (19) : x = \frac{ln ( 63 )}{ln ( 19 )}

x = \frac{ln ( 63 )}{ln ( 19 )}

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