What is the answer to 3^{x+4}=27^{2x-1} ?

The answer to 3^{x+4}=27^{2x-1} is x= 7/5

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3^{x+4}=27^{2x-1}

3^{x + 4} = 2 7^{2 x - 1}

x = \frac{7}{5}

Solution steps

3^{x + 4} = 2 7^{2 x - 1}

Apply exponent rules

x + 4 = 3 (2 x - 1)

Solve

x + 4 = 3 (2 x - 1) : x = \frac{7}{5}

x = \frac{7}{5}

b^{2^{2 x - 17}} = b^{128}

3^{x - 1} + 3^{x} + 3^{x + 1} = 117

2^{2} n = 4^{n}

e^{k} = 2

What is the answer to 3^{x+4}=27^{2x-1} ?
The answer to 3^{x+4}=27^{2x-1} is x= 7/5
Solve for x: 3^{x+4}=27^{2x-1}
The solution is x= 7/5