What is the answer to 5^{x+4}=2^{3x} ?

The answer to 5^{x+4}=2^{3x} is x=(4ln(5))/(3ln(2)-ln(5))

Solve for x: 5^{x+4}=2^{3x}

The solution is x=(4ln(5))/(3ln(2)-ln(5))

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5^{x + 4} = 2^{3 x}

x = \frac{4 ln ( 5 )}{3 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = 13.69723 \dots

Solution steps

5^{x + 4} = 2^{3 x}

Apply exponent rules

(x + 4) ln (5) = 3 x ln (2)

Solve

(x + 4) ln (5) = 3 x ln (2) : x = \frac{4 ln ( 5 )}{3 ln ( 2 ) - ln ( 5 )}

x = \frac{4 ln ( 5 )}{3 ln ( 2 ) - ln ( 5 )}

m^{2} e^{m x} + 6 m e^{m x} + 5 e^{m x} = 0

- 2 e^{2 x} = 0

e^{2 x} + 1 = 3 e^{- x}

5^{5 x - 2} = 45

What is the answer to 5^{x+4}=2^{3x} ?
The answer to 5^{x+4}=2^{3x} is x=(4ln(5))/(3ln(2)-ln(5))
Solve for x: 5^{x+4}=2^{3x}
The solution is x=(4ln(5))/(3ln(2)-ln(5))