What is the answer to 5^x-2=0 ?

The answer to 5^x-2=0 is x=(ln(2))/(ln(5))

The solution is x=(ln(2))/(ln(5))

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5^x-2=0

5^{x} - 2 = 0

x = \frac{ln ( 2 )}{ln ( 5 )}

Decimal Notation

x = 0.43067 \dots

Solution steps

5^{x} - 2 = 0

Add

2

to both sides

5^{x} - 2 + 2 = 0 + 2

Simplify

5^{x} = 2

Apply exponent rules

x ln (5) = ln (2)

Solve

x ln (5) = ln (2) : x = \frac{ln ( 2 )}{ln ( 5 )}

x = \frac{ln ( 2 )}{ln ( 5 )}

2^{x} \cdot 2^{3 x - 8} = 6

a^{x} = b c

2^{x} - 2 = - 2 x + 12

7^{x - 2} = 49

22000 e^{0.05 t} = 11000 e^{0.07 t}