What is the answer to 4^{x-3}=32^{2x+1} ?

The answer to 4^{x-3}=32^{2x+1} is x=-11/8

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4^{x-3}=32^{2x+1}

4^{x - 3} = 3 2^{2 x + 1}

x = - \frac{11}{8}

Decimal Notation

x = - 1.375

Solution steps

4^{x - 3} = 3 2^{2 x + 1}

Apply exponent rules

2 (x - 3) = 5 (2 x + 1)

Solve

2 (x - 3) = 5 (2 x + 1) : x = - \frac{11}{8}

x = - \frac{11}{8}

8^{5 x - 1} = 32

5^{2 x - 1} = 4^{x + 3}

280 = 1400 - 1400 (0.9)^{t}

3^{x} = 33

200 e^{0.063 t} = 600

What is the answer to 4^{x-3}=32^{2x+1} ?
The answer to 4^{x-3}=32^{2x+1} is x=-11/8
Solve for x: 4^{x-3}=32^{2x+1}
The solution is x=-11/8