What is the answer to 2=(1+(0.1)/(52))^{52t} ?

The answer to 2=(1+(0.1)/(52))^{52t} is t=(ln(2))/(52ln(\frac{52.1){52})}

Solve for t: 2=(1+(0.1)/(52))^{52t}

The solution is t=(ln(2))/(52ln(\frac{52.1){52})}

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2 = (1 + \frac{0.1}{52})^{52 t}

t = \frac{ln ( 2 )}{52 ln ( \frac{52.1}{52} )}

Solution steps

2 = (1 + \frac{0.1}{52})^{52 t}

Apply exponent rules

ln (2) = 52 t ln (1 + \frac{0.1}{52})

Solve

ln (2) = 52 t ln (1 + \frac{0.1}{52}) : t = \frac{ln ( 2 )}{52 ln ( \frac{52.1}{52} )}

t = \frac{ln ( 2 )}{52 ln ( \frac{52.1}{52} )}

8^{x - 5} = 16

2^{2 x} + 2^{x + 2} = 12

6^{1 - 4 x} = 5^{x}

8 \cdot 1 0^{2 x - 7} = 3

8^{x} = 125

What is the answer to 2=(1+(0.1)/(52))^{52t} ?
The answer to 2=(1+(0.1)/(52))^{52t} is t=(ln(2))/(52ln(\frac{52.1){52})}
Solve for t: 2=(1+(0.1)/(52))^{52t}
The solution is t=(ln(2))/(52ln(\frac{52.1){52})}