What is the answer to 6^{1-4x}=5^x ?

The answer to 6^{1-4x}=5^x is x=(ln(6))/(ln(6480))

Solve for x: 6^{1-4x}=5^x

The solution is x=(ln(6))/(ln(6480))

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6^{1 - 4 x} = 5^{x}

x = \frac{ln ( 6 )}{ln ( 6480 )}

Decimal Notation

x = 0.20415 \dots

Solution steps

6^{1 - 4 x} = 5^{x}

Apply exponent rules

(1 - 4 x) ln (6) = x ln (5)

Solve

(1 - 4 x) ln (6) = x ln (5) : x = \frac{ln ( 6 )}{ln ( 6480 )}

x = \frac{ln ( 6 )}{ln ( 6480 )}

8 \cdot 1 0^{2 x - 7} = 3

8^{x} = 125

10000 = 2^{t}

2500 = 2000 (1.04)^{t}

x, 30 = 1 0^{x}

What is the answer to 6^{1-4x}=5^x ?
The answer to 6^{1-4x}=5^x is x=(ln(6))/(ln(6480))
Solve for x: 6^{1-4x}=5^x
The solution is x=(ln(6))/(ln(6480))