What is the answer to e^{2x}+2e^x+1=0 ?

The answer to e^{2x}+2e^x+1=0 is No Solution for x\in\mathbb{R}

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e^{2x}+2e^x+1=0

e^{2 x} + 2 e^{x} + 1 = 0

No Solution for x \in R

Solution steps

e^{2 x} + 2 e^{x} + 1 = 0

Apply exponent rules

(e^{x})^{2} + 2 e^{x} + 1 = 0

Rewrite the equation with

e^{x} = u

(u)^{2} + 2 u + 1 = 0

Solve

u^{2} + 2 u + 1 = 0 : u = - 1

u = - 1

Substitute back

u = e^{x},

solve for

x

Solve

e^{x} = - 1 :

No Solution for

x \in R

No Solution for x \in R

432 = 3^{x + 1} \cdot 2^{2 x}

x, 3^{2 x - 3} = 21

1 5^{3 x - 2} = 1 3^{3 x - 2}

4461480 = 6800000 \cdot 0. 9^{x}

ln (e^{2 x + 1}) = 9

What is the answer to e^{2x}+2e^x+1=0 ?
The answer to e^{2x}+2e^x+1=0 is No Solution for x\in\mathbb{R}