What is the answer to 2^{x^2-5x}=4^{x-5} ?

The answer to 2^{x^2-5x}=4^{x-5} is x=5,x=2

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2^{x^2-5x}=4^{x-5}

2^{x^{2} - 5 x} = 4^{x - 5}

x = 5, x = 2

Solution steps

2^{x^{2} - 5 x} = 4^{x - 5}

Apply exponent rules

x^{2} - 5 x = 2 (x - 5)

Solve

x^{2} - 5 x = 2 (x - 5) : x = 5, x = 2

x = 5, x = 2

2 (1 2^{x}) = 190

0. 8^{x} = 0.05

2^{1 - x} = 3^{2 x + 5}

e^{2 x - 3} = 75

3^{2 x} - 5 \cdot 3^{x} - 36 = 0

What is the answer to 2^{x^2-5x}=4^{x-5} ?
The answer to 2^{x^2-5x}=4^{x-5} is x=5,x=2
Solve for x: 2^{x^2-5x}=4^{x-5}
The solution is x=5,x=2