What is the answer to 12^{x^2+2x+3}=1728 ?

The answer to 12^{x^2+2x+3}=1728 is x=0,x=-2

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12^{x^2+2x+3}=1728

1 2^{x^{2} + 2 x + 3} = 1728

x = 0, x = - 2

Solution steps

1 2^{x^{2} + 2 x + 3} = 1728

Apply exponent rules

x^{2} + 2 x + 3 = 3

Solve

x^{2} + 2 x + 3 = 3 : x = 0, x = - 2

x = 0, x = - 2

2^{2 x} = \frac{1}{8}

e^{- x} + 2 x - 1 = 0

2^{8^{x - 2}} = 4^{4^{x - 1}}

4^{2 x + 1} - 65 (4^{x}) + 16 = 0

e^{(9 x)} - 5 e^{(3 x)} + 4 = 0

What is the answer to 12^{x^2+2x+3}=1728 ?
The answer to 12^{x^2+2x+3}=1728 is x=0,x=-2
Solve for x: 12^{x^2+2x+3}=1728
The solution is x=0,x=-2