What is the answer to 3^{x-1}=20 ?

The answer to 3^{x-1}=20 is x=(ln(20))/(ln(3))+1

Solve for x: 3^{x-1}=20

The solution is x=(ln(20))/(ln(3))+1

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3^{x - 1} = 20

x = \frac{ln ( 20 )}{ln ( 3 )} + 1

Decimal Notation

x = 3.72683 \dots

Solution steps

3^{x - 1} = 20

Apply exponent rules

(x - 1) ln (3) = ln (20)

Solve

(x - 1) ln (3) = ln (20) : x = \frac{ln ( 20 )}{ln ( 3 )} + 1

x = \frac{ln ( 20 )}{ln ( 3 )} + 1

3^{x - 4} = 2

6 4^{x} = 256

2^{2000} = 3 2^{x}

e^{x} = 0.6

13 (1 + e^{- x})^{- 1} = 2

What is the answer to 3^{x-1}=20 ?
The answer to 3^{x-1}=20 is x=(ln(20))/(ln(3))+1
Solve for x: 3^{x-1}=20
The solution is x=(ln(20))/(ln(3))+1