What is the answer to 2^{(x-1)}=3^x ?

The answer to 2^{(x-1)}=3^x is x=(ln(2))/(ln(2)-ln(3))

Solve for x: 2^{(x-1)}=3^x

The solution is x=(ln(2))/(ln(2)-ln(3))

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2^{(x - 1)} = 3^{x}

x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

Solution steps

2^{(x - 1)} = 3^{x}

Apply exponent rules

(x - 1) ln (2) = x ln (3)

Solve

(x - 1) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

324 = 4 (3)^{2 x}

2 5^{x} = 5

1 0^{a} = 76.2

2^{x} + x = 11

1 0^{- x} = 5^{x - 1}

What is the answer to 2^{(x-1)}=3^x ?
The answer to 2^{(x-1)}=3^x is x=(ln(2))/(ln(2)-ln(3))
Solve for x: 2^{(x-1)}=3^x
The solution is x=(ln(2))/(ln(2)-ln(3))