What is the answer to 11^{-8x}=18^{-x+5} ?

The answer to 11^{-8x}=18^{-x+5} is x=(5ln(18))/(-8ln(11)+ln(18))

Solve for x: 11^{-8x}=18^{-x+5}

The solution is x=(5ln(18))/(-8ln(11)+ln(18))

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1 1^{- 8 x} = 1 8^{- x + 5}

x = \frac{5 ln ( 18 )}{- 8 ln ( 11 ) + ln ( 18 )}

Decimal Notation

x = - 0.88700 \dots

Solution steps

1 1^{- 8 x} = 1 8^{- x + 5}

Apply exponent rules

- 8 x ln (11) = (- x + 5) ln (18)

Solve

- 8 x ln (11) = (- x + 5) ln (18) : x = \frac{5 ln ( 18 )}{- 8 ln ( 11 ) + ln ( 18 )}

x = \frac{5 ln ( 18 )}{- 8 ln ( 11 ) + ln ( 18 )}

k, n = 7^{k}

x, 1 0^{x + 2 y} = 5

e^{x} = e^{- x} + 2

9^{x} = 2 7^{(x + 6)}

9^{3 x + 1} = 6

What is the answer to 11^{-8x}=18^{-x+5} ?
The answer to 11^{-8x}=18^{-x+5} is x=(5ln(18))/(-8ln(11)+ln(18))
Solve for x: 11^{-8x}=18^{-x+5}
The solution is x=(5ln(18))/(-8ln(11)+ln(18))