What is the answer to 3^{x^2+2x+6}=27^{x+4} ?

The answer to 3^{x^2+2x+6}=27^{x+4} is x=3,x=-2

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3^{x^2+2x+6}=27^{x+4}

3^{x^{2} + 2 x + 6} = 2 7^{x + 4}

x = 3, x = - 2

Solution steps

3^{x^{2} + 2 x + 6} = 2 7^{x + 4}

Apply exponent rules

x^{2} + 2 x + 6 = 3 (x + 4)

Solve

x^{2} + 2 x + 6 = 3 (x + 4) : x = 3, x = - 2

x = 3, x = - 2

1 3^{x} = 21 3^{- x}

(27)^{x^{2}} = \frac{1}{9 ^{x}}

2^{x} + 2^{x + 2} = \frac{5}{8 ^{b}}

384 e^{8} = (2^{x}) (7)

83 = 1 3^{x}

What is the answer to 3^{x^2+2x+6}=27^{x+4} ?
The answer to 3^{x^2+2x+6}=27^{x+4} is x=3,x=-2
Solve for x: 3^{x^2+2x+6}=27^{x+4}
The solution is x=3,x=-2