What is the answer to (27)^{x^2}= 1/(9^x) ?

The answer to (27)^{x^2}= 1/(9^x) is x=0,x=-2/3

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(27)^{x^2}= 1/(9^x)

(27)^{x^{2}} = \frac{1}{9 ^{x}}

x = 0, x = - \frac{2}{3}

Solution steps

(27)^{x^{2}} = \frac{1}{9 ^{x}}

Apply exponent rules

3 x^{2} = - 2 x

Solve

3 x^{2} = - 2 x : x = 0, x = - \frac{2}{3}

x = 0, x = - \frac{2}{3}

Verify Solutions:

x = 0

True

, x = - \frac{2}{3}

True

The solutions are

x = 0, x = - \frac{2}{3}

2^{x} + 2^{x + 2} = \frac{5}{8 ^{b}}

384 e^{8} = (2^{x}) (7)

83 = 1 3^{x}

8 1^{2 x - 1} = \frac{1}{3}

6^{3 x} = 4^{2 x - 3}

What is the answer to (27)^{x^2}= 1/(9^x) ?
The answer to (27)^{x^2}= 1/(9^x) is x=0,x=-2/3
Solve for x: (27)^{x^2}= 1/(9^x)
The solution is x=0,x=-2/3