What is the answer to 6^{3x}=4^{2x-3} ?

The answer to 6^{3x}=4^{2x-3} is x=-(6ln(2))/(ln(27/2))

Solve for x: 6^{3x}=4^{2x-3}

The solution is x=-(6ln(2))/(ln(27/2))

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6^{3 x} = 4^{2 x - 3}

x = - \frac{6 ln ( 2 )}{ln ( \frac{27}{2} )}

Decimal Notation

x = - 1.59791 \dots

Solution steps

6^{3 x} = 4^{2 x - 3}

Apply exponent rules

3 x ln (6) = (2 x - 3) ln (4)

Solve

3 x ln (6) = (2 x - 3) ln (4) : x = - \frac{6 ln ( 2 )}{ln ( \frac{27}{2} )}

x = - \frac{6 ln ( 2 )}{ln ( \frac{27}{2} )}

3^{x} = 4^{x - 1}

9^{x} - 3^{x + 2} + 18 = 0

1.4 \cdot 0. 9^{x} = 0. 5^{x}

10 0^{\frac{2}{x}} = (1 + 0.1)^{x}

2 (1 0^{x}) + 35 = 179

What is the answer to 6^{3x}=4^{2x-3} ?
The answer to 6^{3x}=4^{2x-3} is x=-(6ln(2))/(ln(27/2))
Solve for x: 6^{3x}=4^{2x-3}
The solution is x=-(6ln(2))/(ln(27/2))