What is the answer to 2(10^x)+35=179 ?

The answer to 2(10^x)+35=179 is x=(ln(72))/(ln(10))

Solve for x: 2(10^x)+35=179

The solution is x=(ln(72))/(ln(10))

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2 (1 0^{x}) + 35 = 179

x = \frac{ln ( 72 )}{ln ( 10 )}

Solution steps

2 (1 0^{x}) + 35 = 179

Move

35

to the right side

2 \cdot 1 0^{x} = 144

Divide both sides by

2

1 0^{x} = 72

Apply exponent rules

x ln (10) = ln (72)

Solve

x ln (10) = ln (72) : x = \frac{ln ( 72 )}{ln ( 10 )}

x = \frac{ln ( 72 )}{ln ( 10 )}

30 = 286.93 (0.973 8^{x})

4^{(x)} + 2^{(x + 2)} = 3

4 \cdot 1 0^{2 x} = 1

lo g_{10} (3^{x}) = 2

5^{x - 4} = 7

What is the answer to 2(10^x)+35=179 ?
The answer to 2(10^x)+35=179 is x=(ln(72))/(ln(10))
Solve for x: 2(10^x)+35=179
The solution is x=(ln(72))/(ln(10))