What is the answer to log_{10}(3^x)=2 ?

The answer to log_{10}(3^x)=2 is x=(2ln(10))/(ln(3))

Solve for x: log_{10}(3^x)=2

The solution is x=(2ln(10))/(ln(3))

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lo g_{10} (3^{x}) = 2

x = \frac{2 ln ( 10 )}{ln ( 3 )}

Solution steps

lo g_{10} (3^{x}) = 2

Rewrite the equation with

3^{x} = u

lo g_{10} (u) = 2

Solve

lo g_{10} (u) = 2 : u = 100

u = 100

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 100 : x = \frac{2 ln ( 10 )}{ln ( 3 )}

x = \frac{2 ln ( 10 )}{ln ( 3 )}

5^{x - 4} = 7

4^{3 x - 1} = 3 2^{x + 6}

(27)^{2 x + 1} = \frac{1}{3}

2^{2 x - 2} = 1

e^{x} = 99

What is the answer to log_{10}(3^x)=2 ?
The answer to log_{10}(3^x)=2 is x=(2ln(10))/(ln(3))
Solve for x: log_{10}(3^x)=2
The solution is x=(2ln(10))/(ln(3))