What is the answer to solvefor x,2^{2x}-2^{x+1}=0 ?

The answer to solvefor x,2^{2x}-2^{x+1}=0 is x=1

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solvefor x,2^{2x}-2^{x+1}=0

solve for

x, 2^{2 x} - 2^{x + 1} = 0

x = 1

Solution steps

2^{2 x} - 2^{x + 1} = 0

Add

2^{x + 1}

to both sides

2^{2 x} - 2^{x + 1} + 2^{x + 1} = 0 + 2^{x + 1}

Simplify

2^{2 x} = 2^{x + 1}

Apply exponent rules

2 x = x + 1

Solve

2 x = x + 1 : x = 1

x = 1

x, t (x) = e^{x}

2 5^{x} - 3 \cdot 5^{x} = 0

3^{2 x - 7} = 81

8^{- x} = 1.2

e^{3 k} = 27

What is the answer to solvefor x,2^{2x}-2^{x+1}=0 ?
The answer to solvefor x,2^{2x}-2^{x+1}=0 is x=1