What is the answer to 25^x-3*5^x=0 ?

The answer to 25^x-3*5^x=0 is x=(ln(3))/(ln(5))

Solve for x: 25^x-3*5^x=0

The solution is x=(ln(3))/(ln(5))

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2 5^{x} - 3 \cdot 5^{x} = 0

x = \frac{ln ( 3 )}{ln ( 5 )}

Solution steps

2 5^{x} - 3 \cdot 5^{x} = 0

Add

3 \cdot 5^{x}

to both sides

2 5^{x} - 3 \cdot 5^{x} + 3 \cdot 5^{x} = 0 + 3 \cdot 5^{x}

Simplify

2 5^{x} = 3 \cdot 5^{x}

Apply exponent rules

2 x ln (5) = ln (3) + x ln (5)

Solve

2 x ln (5) = ln (3) + x ln (5) : x = \frac{ln ( 3 )}{ln ( 5 )}

x = \frac{ln ( 3 )}{ln ( 5 )}

3^{2 x - 7} = 81

8^{- x} = 1.2

e^{3 k} = 27

16 \cdot 4^{x - 4} = 9^{2 x - 3}

5^{x} = 3^{x + 1}

What is the answer to 25^x-3*5^x=0 ?
The answer to 25^x-3*5^x=0 is x=(ln(3))/(ln(5))
Solve for x: 25^x-3*5^x=0
The solution is x=(ln(3))/(ln(5))