What is the answer to 16*4^{x-4}=9^{2x-3} ?

The answer to 16*4^{x-4}=9^{2x-3} is x=-(6ln(3)-4ln(2))/(2(ln(2)-2ln(3)))

Solve for x: 16*4^{x-4}=9^{2x-3}

The solution is x=-(6ln(3)-4ln(2))/(2(ln(2)-2ln(3)))

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16 \cdot 4^{x - 4} = 9^{2 x - 3}

x = - \frac{6 ln ( 3 ) - 4 ln ( 2 )}{2 ( ln ( 2 ) - 2 ln ( 3 ) )}

Decimal Notation

x = 1.26957 \dots

Solution steps

16 \cdot 4^{x - 4} = 9^{2 x - 3}

Apply exponent rules

ln (16) + (x - 4) ln (4) = (2 x - 3) ln (9)

Solve

ln (16) + (x - 4) ln (4) = (2 x - 3) ln (9) : x = - \frac{6 ln ( 3 ) - 4 ln ( 2 )}{2 ( ln ( 2 ) - 2 ln ( 3 ) )}

x = - \frac{6 ln ( 3 ) - 4 ln ( 2 )}{2 ( ln ( 2 ) - 2 ln ( 3 ) )}

5^{x} = 3^{x + 1}

x, A^{x} = BC

e^{x + 2} = 2 k + 1

x, a = 6 4^{x} 4^{y}

2 7^{x + 2} = 9^{6 x + 10}

What is the answer to 16*4^{x-4}=9^{2x-3} ?
The answer to 16*4^{x-4}=9^{2x-3} is x=-(6ln(3)-4ln(2))/(2(ln(2)-2ln(3)))
Solve for x: 16*4^{x-4}=9^{2x-3}
The solution is x=-(6ln(3)-4ln(2))/(2(ln(2)-2ln(3)))