What is the answer to solvefor x,a=64^x4^y ?

The answer to solvefor x,a=64^x4^y is x=(ln(a/(4^y)))/(3ln(4))

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solvefor x,a=64^x4^y

solve for

x, a = 6 4^{x} 4^{y}

x = \frac{ln ( \frac{a}{4 ^{y}} )}{3 ln ( 4 )}

Solution steps

a = 6 4^{x} \cdot 4^{y}

Switch sides

6 4^{x} \cdot 4^{y} = a

Divide both sides by

4^{y}

6 4^{x} = \frac{a}{4 ^{y}}

Apply exponent rules

3 x ln (4) = ln (\frac{a}{4 ^{y}})

Solve

3 x ln (4) = ln (\frac{a}{4 ^{y}}) : x = \frac{ln ( \frac{a}{4 ^{y}} )}{3 ln ( 4 )}

x = \frac{ln ( \frac{a}{4 ^{y}} )}{3 ln ( 4 )}

2 7^{x + 2} = 9^{6 x + 10}

b^{7 - x} = b^{3}

12 5^{x + 1} = 25

\frac{1}{2} = e^{- t}

1 0^{x} = 25.6

What is the answer to solvefor x,a=64^x4^y ?
The answer to solvefor x,a=64^x4^y is x=(ln(a/(4^y)))/(3ln(4))