What is the answer to 16^{x^2-16}-1=0 ?

The answer to 16^{x^2-16}-1=0 is x=4,x=-4

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16^{x^2-16}-1=0

1 6^{x^{2} - 16} - 1 = 0

x = 4, x = - 4

Solution steps

1 6^{x^{2} - 16} - 1 = 0

Add

1

to both sides

1 6^{x^{2} - 16} - 1 + 1 = 0 + 1

Simplify

1 6^{x^{2} - 16} = 1

Apply exponent rules

(x^{2} - 16) ln (16) = ln (1)

Solve

(x^{2} - 16) ln (16) = ln (1) : x = 4, x = - 4

x = 4, x = - 4

(64)^{x} + (16)^{10} - 4 = 0

e^{x^{2}} = 2

- 3.73 = - 4 x e^{- \frac{x}{4}}

(4^{n} \cdot 4^{5})^{3} = 4^{27}

9^{x - 5} = 27

What is the answer to 16^{x^2-16}-1=0 ?
The answer to 16^{x^2-16}-1=0 is x=4,x=-4
Solve for x: 16^{x^2-16}-1=0
The solution is x=4,x=-4