What is the answer to sqrt(3^{2x+1)}=9^{x-1} ?

The answer to sqrt(3^{2x+1)}=9^{x-1} is x= 5/2

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sqrt(3^{2x+1)}=9^{x-1}

3^{2 x + 1} = 9^{x - 1}

x = \frac{5}{2}

Solution steps

3^{2 x + 1} = 9^{x - 1}

Apply exponent rules

(2 x + 1) \frac{1}{2} = 2 (x - 1)

Solve

(2 x + 1) \frac{1}{2} = 2 (x - 1) : x = \frac{5}{2}

x = \frac{5}{2}

1 = e^{x (0.5)}

5 (5^{2 x}) - 126 (5^{x}) + 25 = 0

7^{x} = 2401

(8^{- 3 x}) (2^{x + 1}) = 4^{x + 2}

2^{x} - x^{3} = 0

What is the answer to sqrt(3^{2x+1)}=9^{x-1} ?
The answer to sqrt(3^{2x+1)}=9^{x-1} is x= 5/2
Solve for x: sqrt(3^{2x+1)}=9^{x-1}
The solution is x= 5/2