What is the answer to (8^{-3x})(2^{x+1})=4^{x+2} ?

The answer to (8^{-3x})(2^{x+1})=4^{x+2} is x=-3/10

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(8^{-3x})(2^{x+1})=4^{x+2}

(8^{- 3 x}) (2^{x + 1}) = 4^{x + 2}

x = - \frac{3}{10}

Decimal Notation

x = - 0.3

Solution steps

(8^{- 3 x}) (2^{x + 1}) = 4^{x + 2}

Apply exponent rules

- 8 x + 1 = 2 (x + 2)

Solve

- 8 x + 1 = 2 (x + 2) : x = - \frac{3}{10}

x = - \frac{3}{10}

2^{x} - x^{3} = 0

6 (5^{x - 4}) = 42

9^{x} = 2 7^{3 - x}

2 3^{n} = - (5^{n})

7^{x} - 7 = 35 + 7^{3 - x}

What is the answer to (8^{-3x})(2^{x+1})=4^{x+2} ?
The answer to (8^{-3x})(2^{x+1})=4^{x+2} is x=-3/10
Solve for x: (8^{-3x})(2^{x+1})=4^{x+2}
The solution is x=-3/10