What is the answer to 4^{2-n}= 1/2048 ?

The answer to 4^{2-n}= 1/2048 is n= 15/2

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4^{2-n}= 1/2048

4^{2 - n} = \frac{1}{2048}

n = \frac{15}{2}

Decimal Notation

n = 7.5

Solution steps

4^{2 - n} = \frac{1}{2048}

Apply exponent rules

2 (2 - n) = - 11

Solve

2 (2 - n) = - 11 : n = \frac{15}{2}

n = \frac{15}{2}

3^{6 - x} = 2 7^{x - 2}

5^{- n} = 12 5^{3 n + 5}

e^{x + l n (4)} = 3 e^{x}

x + e^{x} = 1

e^{4 x} = \frac{10}{e ^{- 2 x}}

What is the answer to 4^{2-n}= 1/2048 ?
The answer to 4^{2-n}= 1/2048 is n= 15/2
Solve for n: 4^{2-n}= 1/2048
The solution is n= 15/2