What is the answer to e^{4x}=(10)/(e^{-2x)} ?

The answer to e^{4x}=(10)/(e^{-2x)} is x=(ln(10))/2

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e^{4x}=(10)/(e^{-2x)}

e^{4 x} = \frac{10}{e ^{- 2 x}}

x = \frac{ln ( 10 )}{2}

Solution steps

e^{4 x} = \frac{10}{e ^{- 2 x}}

Apply exponent rules

4 x = ln (10) + 2 x

Solve

4 x = ln (10) + 2 x : x = \frac{ln ( 10 )}{2}

x = \frac{ln ( 10 )}{2}

Verify Solutions:

x = \frac{ln ( 10 )}{2}

True

The solution is

x = \frac{ln ( 10 )}{2}

4^{x + 1} = (\frac{1}{8})^{x}

4^{x} + 5 \cdot 2^{x} = 6

3^{2 (x - 1)} = 7^{2}

4^{7 x - x^{2}} = 4^{12}

5 (2^{2 p + 1}) - 17 (2^{p}) + 3 = 0

What is the answer to e^{4x}=(10)/(e^{-2x)} ?
The answer to e^{4x}=(10)/(e^{-2x)} is x=(ln(10))/2