What is the answer to 4^{x+1}=(1/8)^x ?

The answer to 4^{x+1}=(1/8)^x is x=-2/5

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4^{x+1}=(1/8)^x

4^{x + 1} = (\frac{1}{8})^{x}

x = - \frac{2}{5}

Solution steps

4^{x + 1} = (\frac{1}{8})^{x}

Apply exponent rules

2 (x + 1) = - 3 x

Solve

2 (x + 1) = - 3 x : x = - \frac{2}{5}

x = - \frac{2}{5}

4^{x} + 5 \cdot 2^{x} = 6

3^{2 (x - 1)} = 7^{2}

4^{7 x - x^{2}} = 4^{12}

5 (2^{2 p + 1}) - 17 (2^{p}) + 3 = 0

e^{e^{x}} = 6