What is the answer to 10+e^{-x}=0 ?

The answer to 10+e^{-x}=0 is No Solution for x\in\mathbb{R}

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10+e^{-x}=0

10 + e^{- x} = 0

No Solution for x \in R

Solution steps

10 + e^{- x} = 0

Subtract

e^{- x}

from both sides

10 + e^{- x} - e^{- x} = 0 - e^{- x}

Simplify

10 = - e^{- x}

Move

e^{- x}

to the left side

10 + e^{- x} = 0

Move

10

to the right side

e^{- x} = - 10

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

2 5^{2 x + 4} = 125 \cdot 5^{x - 1}

7^{x + 1} - 2 = 2 (7^{x}) + 3

3^{2 x} - 6 \cdot 3^{x} + 5 = 0

2^{2 x} - 2^{x + 1} - 8 = 0

(\frac{1}{64})^{- x - 3} = 16

What is the answer to 10+e^{-x}=0 ?
The answer to 10+e^{-x}=0 is No Solution for x\in\mathbb{R}