What is the answer to (1/64)^{-x-3}=16 ?

The answer to (1/64)^{-x-3}=16 is x=-7/3

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(1/64)^{-x-3}=16

(\frac{1}{64})^{- x - 3} = 16

x = - \frac{7}{3}

Solution steps

(\frac{1}{64})^{- x - 3} = 16

Apply exponent rules

- 3 (- x - 3) = 2

Solve

- 3 (- x - 3) = 2 : x = - \frac{7}{3}

x = - \frac{7}{3}

2^{2 x - 5} = 8^{x + 7}

2 - e^{x} = 10 e^{- x} - 5

2^{x + 5} = 8^{x}

4 9^{p} = 1

What is the answer to (1/64)^{-x-3}=16 ?
The answer to (1/64)^{-x-3}=16 is x=-7/3
Solve for x: (1/64)^{-x-3}=16
The solution is x=-7/3