What are the solutions to the equation 10x^2+20x-34=0 ?

The solutions to the equation 10x^2+20x-34=0 are x=(-5+sqrt(110))/5 ,x=-(5+sqrt(110))/5

Find the zeros of 10x^2+20x-34=0

The zeros of 10x^2+20x-34=0 are x=(-5+sqrt(110))/5 ,x=-(5+sqrt(110))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 x^{2} + 20 x - 34 = 0

x = \frac{- 5 + 110}{5}, x = - \frac{5 + 110}{5}

Decimal Notation

x = 1.09761 \dots, x = - 3.09761 \dots

Solution steps

10 x^{2} + 20 x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 ( - 34 )}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 (- 34) = 4110

x_{1, 2} = \frac{- 20 \pm 4 110}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 20 + 4 110}{2 \cdot 10}, x_{2} = \frac{- 20 - 4 110}{2 \cdot 10}

x = \frac{- 20 + 4 110}{2 \cdot 10} : \frac{- 5 + 110}{5}

x = \frac{- 20 - 4 110}{2 \cdot 10} : - \frac{5 + 110}{5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 110}{5}, x = - \frac{5 + 110}{5}

\frac{3}{4} x - 6 = 9

\frac{78}{6}

2 (x^{2} - 8) + 7 = - 3

9 m + 63

\frac{1}{3} + \frac{1}{3} - \frac{1}{6}

What are the solutions to the equation 10x^2+20x-34=0 ?
The solutions to the equation 10x^2+20x-34=0 are x=(-5+sqrt(110))/5 ,x=-(5+sqrt(110))/5
Find the zeros of 10x^2+20x-34=0
The zeros of 10x^2+20x-34=0 are x=(-5+sqrt(110))/5 ,x=-(5+sqrt(110))/5